+1443 Meyer rolls two fair, ordinary dice with the numbers 1,2,3,4,5,6 on their sides. What is the probability that AT LEAST one of the dice shows a square number?
+118677 Meyer rolls two fair, ordinary dice with the numbers 1,2,3,4,5,6 on their sides. What is the probability that AT LEAST one of the dice shows a square number?
So one of the numbers must be 1 or 4
the posibilities are
P(1,anything) = (1/6)*1 = 1/6
P(4,anything) = 1/6
so
P(1, or 4 and any number on the other die) = 2/6
P(any number, 1 or 4) = 2/6
so together that is 4/6 trouble is some combinations have been added twice.
P(first die is 1 or 4, AND second die is 1 or 4) = 2/6 * 2/6 = 4/36
So the prob that you want will be 2/6 + 2/6 - 4/36 = 20/36 = 5/9
You can check it by counting them. To get all the combinations just do it in a 6 by 6 grid.
