What is the value of b+c if x^2+bx+c>0 only when x is in (-inf, -2) U (8, inf)?
Let's rewrite (x+m)(x+n) as x^2+bx+c.
This will be positive when x + m and x + n are both positive, or both negative.
This means that at 8, x + m will be 0, and at -2, x + m will be 0.
(x - 8)(x + 2) = x^2 - 6x - 16
-6 - 16 = -22
=^._.^=
