+0

help!! *intermediate algebra*

0
144
3

The closed form sum of $$12 \left[ 1^2 \cdot 2 + 2^2 \cdot 3 + \ldots + n^2 (n+1) \right]$$ for n ≥ 1 is n(n+1)(n+2)(an+b). Find an + b.

Mar 16, 2021

#1
+32410
+3

Presumably you mean find a and b (or, possibly, a + b).

I'm sure you can finish from here.

Mar 16, 2021
#2
0

I am trying to find an + b, how would I do that?

Guest Mar 16, 2021
#3
+32410
+2

Having found a and b (a = 3, b = 1) all you can do with an + b is to set it equal to 3n + 1.

The relationship  is true for all n when a = 3 and b = 1.

Alan  Mar 16, 2021