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In triangle ABC angle bisectors AD, BE, and CF meet at I. If DI = 3, BD = 4, and BI = 5, then compute the area of triangle ABC.

 Nov 7, 2020
 #1
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Have you drawn any diagram?

Can you take a photo of it and post it?

 Nov 7, 2020
 #2
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Sadly, an image wasn't provided...

PseuPneu  Nov 7, 2020
 #3
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No,

I was asking you what you have done to answer this question.

The pic is easy to draw.  I wanted to see if you had drawn it.  

Now it is obvious that you have not.

Can you draw it and upload a pic to this website, please?

 

People here want to help you but doing all the work and all the thinking for you will not help you at all.

 

I will admit, that although the pic is easy I do not think the question is. (I do not have an answer yet)

If you cannot even draw the pic then you are not advanced enough to answer the question.

 

If you want I am happy to brain storm it with you but I want input from you.

Melody  Nov 7, 2020
 #4
avatar+111600 
+2

After an exhausting amount of effort I do have the correct answer.

(there is probably an easier way - using some acceptable pre-knowledge)

 

I am happy to help you arrive at it also if you are prepared to interact with me.

 

If anyone else is seriously interested I am happy to work through it with you too.

Just make a post to show your interest. 

Please talk about what you have tried and a pic would be nice,

 Nov 7, 2020
edited by Melody  Nov 7, 2020
 #6
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So sorry, I had to go to bed since it was already nearing 12 AM...
I will try my best to draw the picture now.

PseuPneu  Nov 7, 2020
 #7
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Thank you for your time.  
I managed to figure this one out...

PseuPneu  Nov 7, 2020
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Triangle ABC is an isosceles triangle with the base of 8 units.

 

angle (B) = 2(arctan3/4)

 

angle (A/2) = 90 - angle (B)

 

height AD = BD / tan(A/2)

 

area = BD * AD = 54.85714289 units squared

 Nov 7, 2020

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