The minute hand of a 12-hour clock measures 10 cm from its tip to the center of the clock face, and the hour hand from its tip to the center of the clock face is 5 cm. What is the sum of the distances, in meters, traveled by the tips of both hands in one 12-hour period? Express your answer to the nearest thousandth of a meter.

Guest Apr 20, 2021

#1**+1 **

circumference of hour hand circle = 2π( 5 cm ) = 10π cm

circumference of minute hand circle = 2π( 10 cm ) = 20π cm

distance traveled by tip of hour hand = 2 * 10π cm = 20π cm

distance traveled by tip of minute hand = 24 * 20π cm = 480π cm

20π cm + 480π cm = 500π cm = 5π meters ≈ 15.708 meters

MyHoneyBunches Apr 20, 2021

#2**+1 **

Hey MHB.... hour hand makes ONE revolution in 12 hours minute hand makes 12 revs

ElectricPavlov
Apr 20, 2021

#4**+1 **

Well ...your answer has hour hand making 2 revs and minute hand making 24 revs....thought you might edit your answer.....

ElectricPavlov
Apr 20, 2021

#5

#6**+1 **

Sorry......you can re-post it though....

*** edited ***

distance traveled by tip of hour hand = 1 * 10π cm = 10π cm

distance traveled by tip of minute hand = 12 * 20π cm = 240π cm

250 pi cm =~ 7.854 meters

ElectricPavlov
Apr 20, 2021