The minute hand of a 12-hour clock measures 10 cm from its tip to the center of the clock face, and the hour hand from its tip to the center of the clock face is 5 cm. What is the sum of the distances, in meters, traveled by the tips of both hands in one 12-hour period? Express your answer to the nearest thousandth of a meter.
circumference of hour hand circle = 2π( 5 cm ) = 10π cm
circumference of minute hand circle = 2π( 10 cm ) = 20π cm
distance traveled by tip of hour hand = 2 * 10π cm = 20π cm
distance traveled by tip of minute hand = 24 * 20π cm = 480π cm
20π cm + 480π cm = 500π cm = 5π meters ≈ 15.708 meters
Hey MHB.... hour hand makes ONE revolution in 12 hours minute hand makes 12 revs
But thats the thing I can't anymore, EP