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# help math problem

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The minute hand of a 12-hour clock measures 10 cm from its tip to the center of the clock face, and the hour hand from its tip to the center of the clock face is 5 cm. What is the sum of the distances, in meters, traveled by the tips of both hands in one 12-hour period? Express your answer to the nearest thousandth of a meter.

Apr 20, 2021

#1
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circumference of hour hand circle  =  2π( 5 cm )  =  10π cm

circumference of minute hand circle  =  2π( 10 cm )  =  20π cm

distance traveled by tip of hour hand  =  2 * 10π cm  =  20π cm

distance traveled by tip of minute hand  =  24 * 20π cm  =  480π cm

20π cm + 480π cm   =   500π cm   =   5π  meters   ≈   15.708 meters

Apr 20, 2021
#2
+1

Hey MHB.... hour hand makes ONE revolution in 12 hours     minute hand makes 12 revs

ElectricPavlov  Apr 20, 2021
#3
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Okaaaaaaaaaaay, EP

MyHoneyBunches  Apr 20, 2021
#4
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ElectricPavlov  Apr 20, 2021
#5
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But thats the thing I can't anymore, EP

Apr 20, 2021
#6
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Sorry......you can re-post it though....

*** edited ***

distance traveled by tip of hour hand  =  1 * 10π cm  =  10π cm

distance traveled by tip of minute hand  =  12 * 20π cm  =  240π cm

250 pi cm =~ 7.854 meters

ElectricPavlov  Apr 20, 2021
edited by ElectricPavlov  Apr 20, 2021