what is the sum of all three-digit odd integer palindromes that contain a digit of 2?
+191 #Palindromes are basically numbers that read the same forward and backwards, like 16861
The information three digit odd palindromes give us valuable information. From this we know that both the hundreds digit and the ones digit must be 1,3,5,7 or 9.
Since we need to contain a digit 2, that could now only fall under the tens digit because both the hundreds and the ones digit must be odd.
So, the possible palindromes are:
121
123
125
127
129
321
323
325
327
329
521
523
525
527
529
721
723
725
727
729
921
923
925
927
and 929.
Adding all of them together we get: (121*5+2+4+6+8) + (121*5 + 200*5 +2 +4 +6 +8) + (121*5 + 400*5 +2 +4 +6 +8) + (121*5 + 600*5 +2 +4 +6 +8) +(121*5 + 800*5 +2 +4 +6 +8)
which equals (121*5 +2+4+6+8)*5 + 1000 +2000 + 3000 + 4000
which sums up to 13125, which is the final answer.
+37159 Three digit ODD palindromes that have a '2' in them :
121
323
525
727
929 add these together for your answer......
