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if someone can help me solve this I would appreciate it.

 
zerq152  Feb 15, 2018
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 #1
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\(p^4-1\) is a difference of squares. To make this clearer, the original expression can be rewritten as \(\left(p^2\right)^2-1^2\). Since the original expression is a difference of squares, it is possible to factor it via \((p^2+1)(p^2-1)\). Notice that one of the factors of the original expression is also a difference of squares, namely \(p^2-1\), so it is possible to factor even further. Therefore, the furthest factored expression would be \((p^2+1)(p+1)(p-1)\)

 
TheXSquaredFactor  Feb 15, 2018

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