+0

# help me find the value of the y-intercept

0
180
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(2x+3)(x-2)

Guest Apr 1, 2017

#1
+6309
+3

I think this is the question:

y = (2x + 3)(x - 2)

The y-intercept occurs when x = 0.

So, solve for y when x = 0. Plug in 0 for x and solve for y.

y = (2(0) + 3)((0) - 2)

y = (0 + 3)( 0 - 2)

y = (3)(-2)

y = -6

The point: (0,-6)

hectictar  Apr 1, 2017
Sort:

#1
+6309
+3

I think this is the question:

y = (2x + 3)(x - 2)

The y-intercept occurs when x = 0.

So, solve for y when x = 0. Plug in 0 for x and solve for y.

y = (2(0) + 3)((0) - 2)

y = (0 + 3)( 0 - 2)

y = (3)(-2)

y = -6

The point: (0,-6)

hectictar  Apr 1, 2017
#2
+82721
+1

Remember that, at the y intercept, x will = 0......so....just substitute 0 for the x's and we have that....

y  = (2(0) + 3) ( 0 - 2)   = (3) (-2)   =   - 6    =  the y intercept

CPhill  Apr 1, 2017

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