(2x+3)(x-2)

I think this is the question:

y = (2x + 3)(x - 2)

The y-intercept occurs when x = 0.

So, solve for y when x = 0. Plug in 0 for x and solve for y.

y = (2(0) + 3)((0) - 2)

y = (0 + 3)( 0 - 2)

y = (3)(-2)

y = -6

The point: (0,-6)

Remember that, at the y intercept, x will = 0......so....just substitute 0 for the x's and we have that....

y = (2(0) + 3) ( 0 - 2) = (3) (-2) = - 6 = the y intercept