In parallelogram EFGH, let M be the point on EF such that FM : ME = 3 : 7, and let N be the point on EH such that HN : NE = 2 : 5. Line segments FH and GM intersect at P, and line segments FH and GN intersect at Q. Find PQ / FH.
Draw the diagram. You will notice that △MPF∼△GPH and △HNQ∼△FGQ.
Using the ratio of corresponding sides in these pairs of similar triangles, we have
HQQF=22+5=27
and
HPPF=3+77=107
We suppose HQ:QP:PF=1:a:b (if not, we just divide through the ratio until the first component is 1).
Then,
{1a+b=271+ab=107
Cross-multiplying,
{2a+2b=7−7a+10b=7
Solving gives a=2817 and b=6334. Hence, HQ:QP:PF=34:56:63.
In particular, PQFH=5634+56+63=56153.