Solve each of the following systems of equations. Find all solutions.
a.
(b)
Your Response:
x + y = -1 subtract x from both sides ⇒ y = - 1 - x (1)
3x = 4 - 3y (2)
Note that we can put (1) into (2)...and we have that
3x = 4 - 3 [ 1 - x ] simplify
3x = 4 - 3 + 3x if we subtract 3x from both sides we have
0 = 4 -3
0 = 1 This is never true...so.....strangely.....we have no solutions for x and y !!!
3x - 4y + 2 = 0
10 - 10 y = 10y - 15x
Divide the second equation through by 5 and we get
2 - 2y = 2y - 3x
Add 3x to both sides....subtract 2, 2y from both sides
3x - 4y = - 2 (1)
Subtract 2 from both sides of the first equation and we have
3x - 4y = -2 (2)
Notice that the transformed equations are exactly the same......whenever this occurs, we have infinite solutions for x and y !!!!
One way to express this is to let x be "fixed" and solve any of the equations for y
So......
3x - 4y = -2
3x + 2 = 4y
[ 3x + 2 ] / 4 = y
So....the solution set can be expressed as {x , y } = { x , [3x + 2] / 4 }