help me is confused

Solve for x:

-log(8)/log(x) = -3/2

Take the reciprocal of both sides:

-log(x)/log(8) = -2/3

Multiply both sides by -log(8):

log(x) = (2 log(8))/3

(2 log(8))/3 = log(8^(2/3)) = log(4):

log(x) = log(4)

Cancel logarithms by taking exp of both sides:

x = 4

Remember, DC, that

log a  = b    in exponential form  is  10^b  = a

So

 Log_x (1 / 8) = - 3 / 2   =

x^(-3/2)  =  1/8       take each side to the  (-2/3) power

x  =  (1/8)^(-2/3)    =   [ (1/8)^(1/3) ]^(-2)   =   ( 1 /  ³√8  )^(-2)   =   (1/2)^(-2)

Note now that    (1/a)^(-m)  =  a^m

So

(1/2)^(-2)  =  (2)^2   =  4  =  x

thanks, CPhill I owe you one