x + 3y = - 3 |*(-1)
4x + 3y = 6
- x - 3y = 3
4x + 3y = 6
3x = 9 | : 3
x = 3
3 + 3y = - 3 | - 3
3y = - 6 | : 3
y = 2
Okay, so we begin by picking one of the equations, and solving for either x or y.
I will pick equation 1, and solve for x:
\(x=-3-3y.\)
We now insert this modifyed version of equation 1 into equation 2. By that i mean that we replace x in equation 2 with -3-3y. We do this and obtain:
\(4\cdot(-3-3y)+3y=6\)
which gives us that
\(y=-2.\)
What remains now is to replace y with -2 in any of our expressions that contain both x and y. Its the easiest to insert it into x=-3-3y, since we would otherwise have to solve for x again! We do this and obtain;
\(x=-3-3\cdot(-2)=3.\)