Help Me Please.
Radicals Equation. Solve for x.
√x2+9 +3= x+4
you can just use parentheses like this
(x^2+9) or use the LaTex function...
\(\sqrt{x^2+9}\) + 3 = x+4 simplify by subtracting 3 from both sides of the equation
sqrt(x^2+9) = x+1 Now square both sides
x^2 + 9 = (x+1)^2 Now expand the R side
x^2 + 9 = x^2 + 2x +1 Subtract x^2 from both sides
9 = 2x+1
8=2x
x=4
no it also extends to the +9..I just dont know how to extend it can you tell me?
you can just use parentheses like this
(x^2+9) or use the LaTex function...
\(\sqrt{x^2+9}\) + 3 = x+4 simplify by subtracting 3 from both sides of the equation
sqrt(x^2+9) = x+1 Now square both sides
x^2 + 9 = (x+1)^2 Now expand the R side
x^2 + 9 = x^2 + 2x +1 Subtract x^2 from both sides
9 = 2x+1
8=2x
x=4