Help Me Please.

Radicals Equation. Solve for x.

√x^{2}+9 +3= x+4

ManuelBautista2019 Feb 27, 2018

#3**+2 **

you can just use parentheses like this

(x^2+9) or use the LaTex function...

\(\sqrt{x^2+9}\) + 3 = x+4 simplify by subtracting 3 from both sides of the equation

sqrt(x^2+9) = x+1 Now square both sides

x^2 + 9 = (x+1)^2 Now expand the R side

x^2 + 9 = x^2 + 2x +1 Subtract x^2 from both sides

9 = 2x+1

8=2x

x=4

ElectricPavlov Feb 27, 2018

#2**+1 **

no it also extends to the +9..I just dont know how to extend it can you tell me?

ManuelBautista2019 Feb 27, 2018

#3**+2 **

Best Answer

you can just use parentheses like this

(x^2+9) or use the LaTex function...

\(\sqrt{x^2+9}\) + 3 = x+4 simplify by subtracting 3 from both sides of the equation

sqrt(x^2+9) = x+1 Now square both sides

x^2 + 9 = (x+1)^2 Now expand the R side

x^2 + 9 = x^2 + 2x +1 Subtract x^2 from both sides

9 = 2x+1

8=2x

x=4

ElectricPavlov
Feb 27, 2018