+0

+1
54
6
+980

4√a6b3/ c2

ManuelBautista2019  Feb 26, 2018
edited by ManuelBautista2019  Feb 26, 2018
Sort:

#1
+12143
+1

$$\sqrt[4]{a^6}$$  b^3 / c^2

= (a^6)^1/4  b^3 /c^2

= a^6/4  b^3 c^-2

= a^3/2  b^3 c^-2

or

$$\sqrt[4]{a^6b^3}$$  /  c^2

=  (a^6)^1/4   (b^3)^1/4   c^-2

= a^3/2    b^3/4  c^-2

ElectricPavlov  Feb 26, 2018
#2
+980
+1

Thanks but the radical sign extends to the c2 too

ManuelBautista2019  Feb 26, 2018
edited by ManuelBautista2019  Feb 26, 2018
#6
+12143
0

OK..... How is anyone supposed to KNOW that MB???   I tried TWO possible ways.....but not the third. Please post your equations more clearly so you can get the correct answers in return   Cool?

Use parentheses or extend the radical to cover things which are supposed to be covered!

ElectricPavlov  Feb 26, 2018
#3
+84389
+2

We can write :

a^(6/4) * b^(3/4)  / c^(2/4)  =

a^(3/2) * b^(3/4) / c^(1/2)      multiply top/bottom by c^(1/2)

a^(3/2)*b^(3/4) *c^(1/2)  / c

Note, Manuel, we could also write this as

a^(3/2) * b^(3/4) * c^(-1/2)

CPhill  Feb 26, 2018

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