Help me Please.

\(\sqrt[4]{a^6}\)  b^3 / c^2

= (a^6)^1/4  b^3 /c^2

= a^6/4  b^3 c^-2

= a^3/2  b^3 c^-2

or

\(\sqrt[4]{a^6b^3}\)  /  c^2

=  (a^6)^1/4   (b^3)^1/4   c^-2

= a^3/2    b^3/4  c^-2

Thanks but the radical sign extends to the c² too

We can write :

a^(6/4) * b^(3/4)  / c^(2/4)  =

a^(3/2) * b^(3/4) / c^(1/2)      multiply top/bottom by c^(1/2)

a^(3/2)*b^(3/4) *c^(1/2)  / c

Note, Manuel, we could also write this as

a^(3/2) * b^(3/4) * c^(-1/2)