Help Me, please.

$h=\sqrt{\frac{g^2}{d}-5t}-1$

                                          Add  1  to both sides of the equation.

$h+1=\sqrt{\frac{g^2}{d}-5t}$

                                          Square both sides of the equation.

$(h+1)^2=\frac{g^2}{d}-5t$

                                          Add  5t  to both sides.

$(h+1)^2+5t=\frac{g^2}{d}$

                                                Multiply both sides by  d .

$d[(h+1)^2+5t]=g^2$

                                                Take the ± square root of both sides.

$±\sqrt{d[(h+1)^2+5t]}=g \\~\\ g=±\sqrt{d[(h+1)^2+5t]}$

Thank you!!