+0  
 
+1
123
4
avatar+1317 

Help Me, please.

 

Writing Equations: Find the polynomial function that has the following "zeros". Express the answer without fractions.

 

1/3,4,3

 

f(x)=

ManuelBautista2019  Mar 7, 2018
 #1
avatar+88871 
+1

(x - 1/3)  ( x - 4) ( x - 3)  =

 

(x - 1/3)  ( x^2 - 7x + 12)  =   { distribute the terms in the first set of parentheses over the terms in the second }

 

x (x^2 - 7x + 12)   -  (1/3)   (  x^2 - 7x + 12)  =

 

x^3  - 7x^2  + 12x    - (1/3)x^2  + (7/3) x  - 4         combine like terms

 

x^3  +  ( -7 - 1/3)x^2 +  (12 + 7/3)x  - 4

 

x^3  +  (  -21/3 - 1/3)x^2  +  (36/3 + 7/3)x  - 4  

 

x^3  +  ( -22/3)x^2  +  ( 43/3)x   - 4

 

x^3  - (22/3)x^2  + (43/3)x  - 4

 

Check my math, Manuel....I did this one rather hurriedly.....LOL!!!

 

 

 

cool cool cool

CPhill  Mar 7, 2018
 #2
avatar+1317 
0

it says to express it without fractions

ManuelBautista2019  Mar 7, 2018
 #3
avatar+88871 
+1

OK....try this

 

(3x - 1) ( x - 4) ( x - 3)  = 

 

3 x^3 - 22 x^2 + 43 x - 12

 

 

cool cool cool

CPhill  Mar 7, 2018
 #4
avatar+1317 
+1

Thanks

ManuelBautista2019  Mar 7, 2018

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