+0

0
292
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+156

May 2, 2018

#1
+101084
+2

First one :

We know an opposite side and an adjacent side....the tangent seems most appropriate, here

So we have

tan x  = 11/9       use the tan  inverse  (atan) to find x

atan (11/9)  =  x ≈  50.71° = 51°

Second one....

tan Y  = 6/7          tan Z  = 7/6

Third  one :

We know an angle, the hypotenuse and we are looking for an adjacent side to the angle....the cosine is what we need

cos (26)  = x / 10   multiply both sides by 10

10 cos (26)  = x   ≈  9

Fourth one :

We know an angle, the adjacent side....and we are looking for the hypotenuse....the cosine, again....

cos36  = 12 / x       divide both sides by cos 36......multiply both sides by  x

x   =  12  / cos 36  ≈  14.8

Last one

We know an angle, an adjacent side....and we are looking for the opposite side.....the tangent seems good

tan  40  = x / 5       multiply both sides by  5

5 tan (40)  = x  ≈  4.2

May 2, 2018
#2
+156
+1

Thank you! Thank you! I've been stuck on them. I appreciate the help!

mathelp  May 2, 2018
#3
+101084
+1

OK....no prob   !!!!

CPhill  May 2, 2018