Given that a is an odd multiple of 7767, find the greatest common divisor of 6a^2+49a+108 and 2a+9.
+9 Odd Multiples of 7767 are 1, 3, 9, 863, 2589, 7767
\(6a^2+49a+108\) and \(2a+9\)
Lets do 1:
\(6(1)^2+49(1)+108\)=163
\(2(1)+9\)=11
So GCF is 1
Lets do 3:
\(6(3)^2+49(3)+108\)=309
\(2(3)+9\)=15
So GCF is 3
Lets do 9:
\(6(9)^2+49(9)+108\)=1035
\(2(9)+9\)=27
So GCF is 9
I can go on with the remaining multiples, but I feel like I am not understanding the question.
