+0  
 
0
313
2
avatar

A crate obtained apples and pears. There were 29 more apples than pears at first. After 1/3 of the apples were removed from the crate, there were 5 more apples than pears. What was the total number of apples and pears in the crate at first?

 Sep 17, 2021
 #1
avatar+36916 
+1

a = p + 29

 

remove 1/3 of the apples, leaving 2/3

 

2/3 a = p+ 5           Sub in the red equation for a

2/3 (p+29) = p+5

p = 43     then   a = 72

 Sep 17, 2021
 #2
avatar
0

1/3 of the apples = n + 29

        After removing 1/3 of the apples remaining apples

                            = (n + 29) - (n + 29)/3 = 2 (x + 29)/3

 

 

=> After removing 1/3 of the apples the remaining apples

 

                                = \({2n + 58 \over 3}\)

 Given after removing 1/3 of the apples from the crate

   there were 5 more apples than pears.

  So, 2n+58/3 = n + 5

 

    => 2n + 58 = 3n + 15

    => 3n - 2n = 58 - 15

    =>  n = 43

 

     n + 29 = 43 + 29 = 72

 

72 apples and 43 pears at first.

 Sep 19, 2021

1 Online Users