When you simplify \(\sqrt[3]{24a^4b^6c^{11}}\), what is the sum of the exponents of the variables that are outside the radical?
When you simplify $\sqrt[3]{24a^4b^6c^{11}}$, what is the sum of the exponents of the variables that are outside the radical?
I got 5 but it was wrong...
+118609 \sqrt[3]{24a^4b^6c^{11}}
\(\sqrt[3]{24a^4b^6c^{11}}\\ =\sqrt[3]{8*2*a^3*a*b^3*b^3*c^{9}*c^2}\\ =\sqrt[3]{2^3*a^3*b^3*b^3*c^{9}*2ac^2}\\ =2*a*b*b*c^3*\sqrt[3]{2ac^2}\\ =2ab^2c^3\sqrt[3]{2ac^2}\\ =2^1a^1b^2c^3\sqrt[3]{2ac^2}\\\)
The way I interprete the question the sum of the exponents of the variables that are outside the radical is 7
I expect you forgot the ones. 
