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help me pls

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When you simplify $$\sqrt[3]{24a^4b^6c^{11}}$$, what is the sum of the exponents of the variables that are outside the radical?

When you simplify $\sqrt[3]{24a^4b^6c^{11}}$, what is the sum of the exponents of the variables that are outside the radical?

I got 5 but it was wrong...

Apr 21, 2019

#1
+105463
+1

\sqrt[3]{24a^4b^6c^{11}}

$$\sqrt[3]{24a^4b^6c^{11}}\\ =\sqrt[3]{8*2*a^3*a*b^3*b^3*c^{9}*c^2}\\ =\sqrt[3]{2^3*a^3*b^3*b^3*c^{9}*2ac^2}\\ =2*a*b*b*c^3*\sqrt[3]{2ac^2}\\ =2ab^2c^3\sqrt[3]{2ac^2}\\ =2^1a^1b^2c^3\sqrt[3]{2ac^2}\\$$

The way I interprete the question the sum of the exponents of the variables that are outside the radical is 7

I expect you forgot the ones.

Apr 25, 2019