Ali and Bakar walked from A to B along the same route. Ali started his journey half an hour earlier than bakar .Bakar walked 6 km at an average speed of 4km/h for the whole journey. Both of them arrived at B at the same time. What was Ali's average speed

Guest May 24, 2017

#1**+2 **

examp. 12:00 start Ali Bakar: 4km ->1h

12:30 start Bakar 6km->xh <=> x=3/2h <=> x=90 min +12:30= 2:00

arrived at the same time so Ali arrived at 2 so he do:

6km->2h

ykm->1h <=>y=3km so 3km/h is the Ali's average speed!!!

I hope you understand!!!

Whitespy001
May 24, 2017

#2**+2 **

Average speed = Distance / Time

4= 6/ T, so T =6/4 =1.5 hours - that took Bakar to cover the 6 Km.

Ali's average speed = 6/ (1.5 + .5) =6 / 2 =3 Km/h - Ali's average speed.

Guest May 24, 2017

#3**+2 **

Bakar's Distance divided by his rate = his total time = 6km / [ 4km/h ] = 3/2 hr

And Ali's Distance divided by his unknown rate , R, rate = his total time = 6km / [ R km / h ]

And Bakar's time plus 1/2 hr = Ali's time .......so

(3 / 2) + (1/ 2) = 6 / R simplify

[ 6 + 2] / 4= 6 / R

[ 8 / 4] = 6 / R

2 = 6 / R and we can write

1/2 = R / 6 multiply both sides by 6

3 = R and Ali's rate = 3 km / hr

CPhill
May 24, 2017