Help me with this please sqrt(20)+sqrt(500)+sqrt(80)=nsqrt(5) find N

Solve for n:

 sqrt(20)+sqrt(500)+sqrt(80)=nsqrt(5)   factor the LHS as follows:

sqrt(4x5) + Sqrt(100x5) + sqrt(16x5) =nsqrt(5)

2sqrt(5) + 10sqrt(5) + 4sqrt(5) = nsqrt(5)  factor sqrt(5) on the LHS

sqrt(5)(4+10+2) =nsqrt(5)                             divide both sides by sqrt(5)

n =2+10+4

n=16

n=16

sqrt(20)+sqrt(500)+sqrt(80)=nsqrt(5)

Switch around terms

n*sqrt{5}=sqrt{20}+sqrt{500}+sqrt{80}

Find radicals of sqrt{20}, sqrt{500} and sqrt{80}

sqrt{20}= 2 sqrt{5}

sqrt{500} = 10 sqrt{5}

sqrt{80} = 4 sqrt{5}

Then add radicals together

n*sqrt{5}=16sqrt{5}

Divide by sqrt{5}

n=16