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Help me with this please sqrt(20)+sqrt(500)+sqrt(80)=nsqrt(5) find N

Guest Oct 9, 2017
 #1
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Solve for n:

 sqrt(20)+sqrt(500)+sqrt(80)=nsqrt(5)   factor the LHS as follows:

sqrt(4x5) + Sqrt(100x5) + sqrt(16x5) =nsqrt(5)

2sqrt(5) + 10sqrt(5) + 4sqrt(5) = nsqrt(5)  factor sqrt(5) on the LHS

sqrt(5)(4+10+2) =nsqrt(5)                             divide both sides by sqrt(5)

n =2+10+4

n=16

Guest Oct 9, 2017
edited by Guest  Oct 9, 2017
 #2
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n=16

 

sqrt(20)+sqrt(500)+sqrt(80)=nsqrt(5)

 

Switch around terms

 

n*sqrt{5}=sqrt{20}+sqrt{500}+sqrt{80}

 

Find radicals of sqrt{20}, sqrt{500} and sqrt{80}

 

sqrt{20}= 2 sqrt{5}

sqrt{500} = 10 sqrt{5}

sqrt{80} = 4 sqrt{5}

 

Then add radicals together

 

n*sqrt{5}=16sqrt{5}

Divide by sqrt{5}

n=16

NediaMaster  Oct 9, 2017

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