A roller coaster car with a mass of 5,178 kg is at the top of a incline that is 26 m high. Calculate the amount of kinetic energy the car has when it reaches the bottom of the hill. *Assume there is no friction.*

TOK002
Feb 21, 2015

#1**+5 **

If there is no friction then the loss of potential energy as the roller coaster falls will equal the gain in kinetic energy of the roller coaster car.

so kinetic energy gained = m x g x h

therefore KE = 5178 x 10 x 26 Joules assuming the acceleration due to gravity g = 10 m/s^{2}

Therefore KE gained = 1,346,280 Joules or 1.35 MJ

Guest Feb 21, 2015

#1**+5 **

Best Answer

If there is no friction then the loss of potential energy as the roller coaster falls will equal the gain in kinetic energy of the roller coaster car.

so kinetic energy gained = m x g x h

therefore KE = 5178 x 10 x 26 Joules assuming the acceleration due to gravity g = 10 m/s^{2}

Therefore KE gained = 1,346,280 Joules or 1.35 MJ

Guest Feb 21, 2015