+111 Nell and David each have some money. If Nell gives David $16, both of
them will have the same amount of money. If David gives Nell $9, the
amount of money Nell has to the amount of money David has will be in
the ratio 6:1. How much money do the two boys have in all?
+15073 How much money do the two boys have in all?
Hello Ticon!
n−16 $=d+16 $n=d+32 $(d−9 $):(n+9 $)=1:66d−54 $=n+9 $6d−54 $=d+32 $+9 $5d=95 $
d=19 $n=51 $n+d=70 $
!
+237 Let the amount of money Nell have = N,
And the amount of money David have = D
Nell David
Initiallly N D
Case 1 N - 16 D + 16
Case 2 N + 9 D - 9
Case 1 --> When Nell gives David $16,
Then both have the same amount.
So, N - 16 = D + 16
N = D + 16 + 16 = D + 32
Case 2 --> When David gives Nell $9,
Nell and David's amount will be in
The ratio 6:1.
(N + 9)/D - 9 = 6/1
N + 9 = 6D - 54
N = 6D - 63
After equating the equations from both cases,
We will get N => D + 32 = 6D - 63
32 + 63 = 6D - D
95 = 5D
D = 95/5 = $19
And, N = D + 32
Nell have $51 and David have
$19. Together they have $(51 + 19)
= $70
