+111 Nell and David each have some money. If Nell gives David $16, both of
them will have the same amount of money. If David gives Nell $9, the
amount of money Nell has to the amount of money David has will be in
the ratio 6:1. How much money do the two boys have in all?
+15000 How much money do the two boys have in all?
Hello Ticon!
\(n-16\ $=d+16\ $\\ n=d+32\ $\\ (d-9\ $):(n+9\ $)=1:6\\ 6d-54\ $=n+9\ $\\ 6d-54\ $=d+32\ $+9\ $\\ 5d=95\ $\)
\(d=19\ $\\ n=51\ $\\ n+d=70\ $\)
!
+237 Let the amount of money Nell have = N,
And the amount of money David have = D
Nell David
Initiallly N D
Case 1 N - 16 D + 16
Case 2 N + 9 D - 9
Case 1 --> When Nell gives David $16,
Then both have the same amount.
So, N - 16 = D + 16
N = D + 16 + 16 = D + 32
Case 2 --> When David gives Nell $9,
Nell and David's amount will be in
The ratio 6:1.
(N + 9)/D - 9 = 6/1
N + 9 = 6D - 54
N = 6D - 63
After equating the equations from both cases,
We will get N => D + 32 = 6D - 63
32 + 63 = 6D - D
95 = 5D
D = 95/5 = $19
And, N = D + 32
Nell have $51 and David have
$19. Together they have $(51 + 19)
= $70
