+19 Triangle ABC is rotated completely around side BC, sweeping out a solid in space. Find the volume of the solid.
AB = 5, AC = 5, CB = 8
i dont really get how this works help plz!!
+1768 The solid formed by rotating triangle ABC around side BC is a cone. Here's how to find its volume:
Identify the cone's dimensions:
Radius (r): During the rotation, side AC traces out the base of the cone
Since AC = 5, the base radius (r) of the cone is 5/2 (half the length of AC becomes the radius).
Height (h): As the triangle rotates, side AB acts as the height of the cone. Therefore, the height (h) of the cone is 5 (AB length).
Formula for Cone Volume: The volume of a cone is calculated using the formula: Volume = (1/3) * π * r^2 * h
Substitute Values and Solve: Volume = (1/3) * π * [(5/2)^2] * 5 Volume = (1/3) * π * (25/4) * 5 Volume = (125/12) * π
Answer: The volume of the solid is (125/12)π cubic units.
