+738 \(\dbinom{223}{221}=\dfrac{223!}{221! \cdot2!}=\dfrac{222\cdot223}{2}=111\cdot223=\boxed{24753}\)
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+876 Lol another alcumus question.
Note that \(\binom{n}{k}=\binom{n}{n-k}\) or you could just do it the general way. (Same easy)
\(\binom{223}{221}=\binom{223}{2}=\frac{223!}{221!2!} = \frac{223\cdot222}{2}=223\cdot111\)=59393
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Note: I may be tricking you! ;)
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This is to prove if you are just here for the answers or not. All these people put lots of time in this and most people just snatch the answers.
