In one design being considered for the container shaped like a cylinder, the container will have a height of 12 inches. What will be the radius of the container, to the nearest tenth of an inch? volume being 258.75 cubic inches
In one design being considered for the container shaped like a cylinder, the container will have a height of 12 inches. What will be the radius of the container, to the nearest tenth of an inch? volume being 258.75 cubic inches
r = radius
h = height
V = volume
\(\begin{array}{rcll} V_{\text{cylinder}} &=& \pi \cdot r^2 \cdot h\\\\ pi \cdot r^2 \cdot h &=& V_{\text{cylinder}} \qquad & | \qquad :h \\ pi \cdot r^2 &=& \frac{ V_{\text{cylinder}} } {h} \qquad & | \qquad :\pi \\ r^2 &=& \frac{ V_{\text{cylinder}} } {h \cdot \pi} \qquad & | \qquad \sqrt{} \\ \end{array}\)
\(\boxed{~ \begin{array}{rcll} r &=& \sqrt{ \frac{ V_{\text{cylinder}} } { \pi \cdot h } } \qquad & | \qquad h = 12\ \text{in} \qquad V_{\text{cylinder}} = 258.75\ \text{in}^3 \\\\ r &=& \sqrt{ \frac{ 258.75\ \text{in}^3 } { \pi \cdot 12\ \text{in} } } \\ r &=& \sqrt{ \frac{ 258.75\ \text{in}^2 } { \pi \cdot 12\ } } \\ r &=& \sqrt{ \frac{ 258.75 } { \pi \cdot 12\ } }\ \text{in} \\ r &=& \sqrt{ 6.86355692084 }\ \text{in} \\ r &=& 2.61983910209\ \text{in} \\ \mathbf{r} & \mathbf{=} & \mathbf{2.6 \ \text{in} } \qquad (\text{rounded})\\ \end{array} ~}\)
In one design being considered for the container shaped like a cylinder, the container will have a height of 12 inches. What will be the radius of the container, to the nearest tenth of an inch? volume being 258.75 cubic inches
r = radius
h = height
V = volume
\(\begin{array}{rcll} V_{\text{cylinder}} &=& \pi \cdot r^2 \cdot h\\\\ pi \cdot r^2 \cdot h &=& V_{\text{cylinder}} \qquad & | \qquad :h \\ pi \cdot r^2 &=& \frac{ V_{\text{cylinder}} } {h} \qquad & | \qquad :\pi \\ r^2 &=& \frac{ V_{\text{cylinder}} } {h \cdot \pi} \qquad & | \qquad \sqrt{} \\ \end{array}\)
\(\boxed{~ \begin{array}{rcll} r &=& \sqrt{ \frac{ V_{\text{cylinder}} } { \pi \cdot h } } \qquad & | \qquad h = 12\ \text{in} \qquad V_{\text{cylinder}} = 258.75\ \text{in}^3 \\\\ r &=& \sqrt{ \frac{ 258.75\ \text{in}^3 } { \pi \cdot 12\ \text{in} } } \\ r &=& \sqrt{ \frac{ 258.75\ \text{in}^2 } { \pi \cdot 12\ } } \\ r &=& \sqrt{ \frac{ 258.75 } { \pi \cdot 12\ } }\ \text{in} \\ r &=& \sqrt{ 6.86355692084 }\ \text{in} \\ r &=& 2.61983910209\ \text{in} \\ \mathbf{r} & \mathbf{=} & \mathbf{2.6 \ \text{in} } \qquad (\text{rounded})\\ \end{array} ~}\)