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A karate expert breaks a stack of bricks with his bare hand. If the force applied is 520 newtons and the impact time is 0.5 × 10ȳ seconds, what is the value of impuls

 Jan 13, 2016

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 #2
avatar+26367 
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A karate expert breaks a stack of bricks with his bare hand. If the force applied is 520 newtons and the impact time is 0.5 × 10ȳ seconds, what is the value of impuls

 

I assume

\(F = 520\ N\)

\(t = 0.5 \cdot 10^{-3} \ s\)

\(p = \text{impuls in}\ Ns\)

 

 

\(\begin{array}{rcl} p &=& F\cdot t\\ p &=& 520\ N \cdot 0.5 \cdot 10^{-3} \ s\\ p &=& 520\cdot 0.5 \cdot 10^{-3} \ Ns\\ p &=& 520\cdot 0.0005 \ Ns\\ p &=& 0.26 \ Ns\\ \end{array}\)

 

laugh

 Jan 14, 2016
 #1
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i dont know how to work it out

 Jan 13, 2016
 #2
avatar+26367 
+5
Best Answer

A karate expert breaks a stack of bricks with his bare hand. If the force applied is 520 newtons and the impact time is 0.5 × 10ȳ seconds, what is the value of impuls

 

I assume

\(F = 520\ N\)

\(t = 0.5 \cdot 10^{-3} \ s\)

\(p = \text{impuls in}\ Ns\)

 

 

\(\begin{array}{rcl} p &=& F\cdot t\\ p &=& 520\ N \cdot 0.5 \cdot 10^{-3} \ s\\ p &=& 520\cdot 0.5 \cdot 10^{-3} \ Ns\\ p &=& 520\cdot 0.0005 \ Ns\\ p &=& 0.26 \ Ns\\ \end{array}\)

 

laugh

heureka Jan 14, 2016

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