Loading [MathJax]/jax/output/SVG/jax.js
 
+0  
 
0
951
2
avatar

i need help with this problem so can you help me please 

 

 

|0.7x+5|>6.7

 Sep 22, 2017

Best Answer 

 #2
avatar+2446 
+1

Absolute value inequalities are not that simple! You can't simply just ignore them.

 

|0.7x+5|>6.7 The absolute value always splits your answer into the positive and negative answer.
0.7x+5>6.7 (0.7x+5)>6.7

 

Now that the absolute value has been accounted for, we should now solve for x in both equations.
7x+50>67 0.7x+5<6.7

 

Dividing by -1 causes a flipflop of the inequality sign.
7x+50>67 7x+50<67

 

Subtract 50 on both sides.
7x>17 7x<117

 

Divide by 7 on both sides.
x>177 x<1177

 

 
   

 

This is your answer. Since the greater than symbol will cause an "or" statement, we know that solutions are the following:

 

x>177orx<1177

 Sep 22, 2017
 #1
avatar
0

|0.7x+5|>6.7   Remove the absolute value

 

0.7x + 5 > 6.7  subtract 5 from both sides

0.7x > 1.7          divide both sides by 0.7

x > 2.42857

 Sep 22, 2017
 #2
avatar+2446 
+1
Best Answer

Absolute value inequalities are not that simple! You can't simply just ignore them.

 

|0.7x+5|>6.7 The absolute value always splits your answer into the positive and negative answer.
0.7x+5>6.7 (0.7x+5)>6.7

 

Now that the absolute value has been accounted for, we should now solve for x in both equations.
7x+50>67 0.7x+5<6.7

 

Dividing by -1 causes a flipflop of the inequality sign.
7x+50>67 7x+50<67

 

Subtract 50 on both sides.
7x>17 7x<117

 

Divide by 7 on both sides.
x>177 x<1177

 

 
   

 

This is your answer. Since the greater than symbol will cause an "or" statement, we know that solutions are the following:

 

x>177orx<1177

TheXSquaredFactor  Sep 22, 2017

2 Online Users

avatar