+40 If \(a=4, b=2,\)and \(c=-5\), then what is the value of \(\sqrt[3]{4a^4b^5} + \dfrac{a - c}{(b+c)^2}?\)
+1908 Let's plug everything in and go from there.
Plugging in 4, 2, and -5,
We have \(\sqrt[3]{4(4^4)(2^5)}+\frac{4-(-5)}{(2-5)^2}\)
Simplfying, we get
\(\sqrt[3]{256*32*4}+\frac{9}{(-3)^2}\\ = \sqrt[3]{32768}+1\\ =32+1\\ =33\)
So our final answer is 33.
Thanks! :)
+1908 Let's plug everything in and go from there.
Plugging in 4, 2, and -5,
We have \(\sqrt[3]{4(4^4)(2^5)}+\frac{4-(-5)}{(2-5)^2}\)
Simplfying, we get
\(\sqrt[3]{256*32*4}+\frac{9}{(-3)^2}\\ = \sqrt[3]{32768}+1\\ =32+1\\ =33\)
So our final answer is 33.
Thanks! :)
