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An investment is advertised as returning 0.6% every month, compounded monthly. If $10,000 is invested, the growth can be modeled by the equation A(t) = 10,000(1.006)^12t. What is the equivalent annual growth rate for this investment (rounded to the nearest tenth of a percent) and what is it worth (rounded to the nearest thousand dollar) after 20 years?

 

Hint: Find the value of 1.00612 on your calculator.

 

A. 5.0% and $42,000 

B. 7.2% and $11,000 

C. 7.4% and $42,000 

D. 7.2% and $40,000

 Feb 22, 2016
 #1
avatar+2592 
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.6% monthly correct? And 12 months right? .6*12=7.2

That leaves option b and C

We can rule B out with common sense. Is $10,000 gonna earn only $1,000 in 20 years? No

But algebraically shown here

10000(1.006)^(12*20) = 42025.74 Where 20 is T in time

This isn't rounding to 40,000 but it is farther away from $11,000 by a longshot

 Feb 22, 2016
 #2
avatar+129849 
0

Spawn....I think the  annual growth rate  = 1.006^12  = about 7.4%

 

So....after 20 years, assuming that we want to use th annual growth rate formula, we have

 

10000 (1 + .074)^20  = about  $41,695  = $42000 [rounded per instructions]

 

And...as you point out.....C   is correct

 

 

cool cool cool

 Feb 22, 2016

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