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# Help! Need answers in two days max!

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Find $$log_23\cdot log_34...log_(127)128$$

Nov 7, 2022

#1
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By the way, the (127) was supposed to be the bottom number, but the latex wouldn't allow more than one digit.

Nov 7, 2022
#4
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You needed to put the 127 in parenthesis, not brackets, they are the curly ones  {127 }

Melody  Nov 7, 2022
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$$log_23\cdot log_34...log_{127}128\\ =\frac{log3}{log2}\cdot \frac{log4}{log3}\dots \cdot \frac{log128}{log127}\\ cancel\\ =\frac{log128}{log2}\\ =\frac{log2^7}{log2}\\ =\frac{7log2}{log2}\\ =7$$

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Nov 7, 2022
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thank you!

Nov 8, 2022