5 cents in 1964. It was 49 cents in 2014. Using your linear model, find the year in which postage was 37 cents. Round to a whole year.
5 cents in 1964. It was 49 cents in 2014. Using your linear model, find the year in which postage was 37 cents. Round to a whole year.
\(\begin{array}{rcl} \dfrac{49-5}{2014-1964} &=& \dfrac{37-5}{y-1964} \\ \dfrac{44}{50} &=& \dfrac{32}{y-1964} \\ y-1964 &=& \dfrac{32\cdot 50}{44} \\ y &=& 1964 + \dfrac{32\cdot 50}{44} \\ y &=& 1964 + 36.\overline{36}\\ y &=& 2000.\overline{36}\\ \mathbf{y} & \mathbf{=} & \mathbf{2000}\\ \end{array}\)
The year in whitch postage was 37 cents was 2000
5 cents in 1964. It was 49 cents in 2014. Using your linear model, find the year in which postage was 37 cents. Round to a whole year.
Let 1964=year0 so 2014=year 50
year x | 0 | 50 |
price y | 5 | 49 |
y=m*x +5
49=m*50+5
44=50m
m=44/50 = 88/100 = 0.88
so
y=0.88x+5
Find x when y=37
37=0.88x+5
32=0.88x
x=32/0.88 = 36 to the nearest whole.
1964+36 = 2000
So if the linear model is accurate then the price was 37c in the year 2000.
5 cents in 1964. It was 49 cents in 2014. Using your linear model, find the year in which postage was 37 cents. Round to a whole year.
\(\begin{array}{rcl} \dfrac{49-5}{2014-1964} &=& \dfrac{37-5}{y-1964} \\ \dfrac{44}{50} &=& \dfrac{32}{y-1964} \\ y-1964 &=& \dfrac{32\cdot 50}{44} \\ y &=& 1964 + \dfrac{32\cdot 50}{44} \\ y &=& 1964 + 36.\overline{36}\\ y &=& 2000.\overline{36}\\ \mathbf{y} & \mathbf{=} & \mathbf{2000}\\ \end{array}\)
The year in whitch postage was 37 cents was 2000