A packet of sugar was used to fill up 2 identical containers. Judy used half the sugar from the first container and 3/4 of the sugar from the second container. If the total amount of sugar left in the 2 containers is 255g, how much sugar was there in the packet at first?
+118667 A packet of sugar was used to fill up 2 identical containers. Judy used half the sugar from the first container and 3/4 of the sugar from the second container. If the total amount of sugar left in the 2 containers is 255g, how much sugar was there in the packet at first?
There is a half left in one and 1/4 left in the other so there is 3/4 of one container left
If you average these then you get 3/8 of the original sugar is left.
3/8 of S = 255
s = 255 divided by 3/8
from the forum calculator:
255/(3/8) = 680
The original packet had 680g of sugar.
check
1/2 of 680 = 340
1/2 of 340= 170
1/4 of 340 = 85
170 + 85 = 255 g good :)
+118667 A packet of sugar was used to fill up 2 identical containers. Judy used half the sugar from the first container and 3/4 of the sugar from the second container. If the total amount of sugar left in the 2 containers is 255g, how much sugar was there in the packet at first?
There is a half left in one and 1/4 left in the other so there is 3/4 of one container left
If you average these then you get 3/8 of the original sugar is left.
3/8 of S = 255
s = 255 divided by 3/8
from the forum calculator:
255/(3/8) = 680
The original packet had 680g of sugar.
check
1/2 of 680 = 340
1/2 of 340= 170
1/4 of 340 = 85
170 + 85 = 255 g good :)
+129850 Call the amount that one container could hold, x......so.... 2x fills both containers, and she uses (1/2)x + (3/4)x = (5/4)x and has 255g left....so....
Amt remaining + amt used = amt in both containers
255 + (5/4)x = 2x simplify
255 = (3/4)x multiply both sides by (4/3)
340 = x
So 2(340) = 680g and that's how much sugar was in the packet
