A certain polygon has three angles that measure 120 degrees and the rest of its angles measure 150 degrees. How many sides does the polygon have?

Guest Jun 4, 2020

#1**0 **

If three angles contain a total of 120^{o} and the total of all the other angles is 150^{o} -- and if we are talking about

interior angles -- the sum of the interior angles is 270^{o}.

This is impossible ...

geno3141 Jun 4, 2020

#5**-1 **

He/she/idk never said that there was only one other side. It doesn't have to be a rectangle. Just a polygon. Possible.

Thelittlekidnextdoor
Jun 5, 2020

#2**+1 **

I'm just going to straight up tell you the formula ffor trial and error. I don't know any smarter way because I'm not smart. :P a/180+2=n. N is how many sides, and a is the amount of angles. I got this from a=(n-2)/180. So you do... 360 also 120*3. (360+150*n)/180+2. Solve this multiple times until you get a whole number. BTW... It's 9 sides. (360+150*6)/180+2=9.

Guest Jun 5, 2020

#3**-1 **

I'm just going to straight up tell you the formula ffor trial and error. I don't know any smarter way because I'm not smart. :P a/180+2=n. N is how many sides, and a is the amount of angles. I got this from a=(n-2)/180. So you do... 360 also 120*3. (360+150*n)/180+2. Solve this multiple times until you get a whole number. BTW... It's 9 sides. (360+150*6)/180+2=9.

Thelittlekidnextdoor Jun 5, 2020