A certain polygon has three angles that measure 120 degrees and the rest of its angles measure 150 degrees. How many sides does the polygon have?
+23245 If three angles contain a total of 120o and the total of all the other angles is 150o -- and if we are talking about
interior angles -- the sum of the interior angles is 270o.
This is impossible ...
+6 He/she/idk never said that there was only one other side. It doesn't have to be a rectangle. Just a polygon. Possible.
I'm just going to straight up tell you the formula ffor trial and error. I don't know any smarter way because I'm not smart. :P a/180+2=n. N is how many sides, and a is the amount of angles. I got this from a=(n-2)/180. So you do... 360 also 120*3. (360+150*n)/180+2. Solve this multiple times until you get a whole number. BTW... It's 9 sides. (360+150*6)/180+2=9.
+6 I'm just going to straight up tell you the formula ffor trial and error. I don't know any smarter way because I'm not smart. :P a/180+2=n. N is how many sides, and a is the amount of angles. I got this from a=(n-2)/180. So you do... 360 also 120*3. (360+150*n)/180+2. Solve this multiple times until you get a whole number. BTW... It's 9 sides. (360+150*6)/180+2=9.
