+0  
 
0
65
1
avatar

 

How many integers n can be used such that the quantity |2n^2 + 3n + 11 - n^2 + 9n| results in a prime number?

 Jun 21, 2022

Best Answer 

 #1
avatar+33053 
+4

2n^2 + 3n + 11 - n^2 + 9n  can be written as n^2 + 12n + 11 which, in turn can be factored as (n + 1)(n + 11).

 

So what does this tell you, remembering that a prime number has no factors other than itself and 1?

 Jun 21, 2022
 #1
avatar+33053 
+4
Best Answer

2n^2 + 3n + 11 - n^2 + 9n  can be written as n^2 + 12n + 11 which, in turn can be factored as (n + 1)(n + 11).

 

So what does this tell you, remembering that a prime number has no factors other than itself and 1?

Alan Jun 21, 2022

10 Online Users

avatar
avatar
avatar