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Solve \(x + 1 = \sqrt[4]{x^4 + 4x^3 - x}\)

 Jul 18, 2020
 #1
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square both sides

 

x^2 + 2x+1   =   \(\sqrt[2]{x^4+4x^3-x}\)      square both sides again

 

x^4 + 4x^3 + 6x^2 + 4x +1    =    x^4 + 4x^3 - x

 

6x^2 + 5x + 1 = 0    

                   quadratic formula shows   x = -1/3   and  -1/2

 Jul 18, 2020

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