3 -2i lies in Quadrant IV
Multiplying this by i^2 gives us
(3 - 2i) * i^2 = 3i^2 - 2i^3 = - 3 - 2 (-i) = -3 + 2i
This is a 180° rotation counter-clockwise
The new product lies in Quadrant II
i jsut went and plotted it and also found that it was in quad 4! bu the rest of the info makes sense as well. thank you!
everything was correct, but it was suppsoed to be 90 degress. I got it wrong. Could you explain ?
Mmmmm...I don't see how they got that ....but.....I'm not an expert on this !!!!
See the graph here : https://www.desmos.com/calculator/g6co3qmnlt
We can imagine these points as being in the complex plane
The line y = (-2/3)x goes through both points .....so...they are separated by 180°
Note that if we multiply (3 - 2i) by i^3 we get 3i^3 - 2i^4 = -3i - 2 = -2 - 3i which is a 90° rotation clockwise and puts the product in Q3
Maybe someone else on here knows why 90° is correct
I suspect you dragged 180° into the 2nd box. However, the second box requires the rotation under multiplication by i, not by i2. Multiplying by i is a 90° rotation.