+128456 3 -2i lies in Quadrant IV
Multiplying this by i^2 gives us
(3 - 2i) * i^2 = 3i^2 - 2i^3 = - 3 - 2 (-i) = -3 + 2i
This is a 180° rotation counter-clockwise
The new product lies in Quadrant II
+1993 i jsut went and plotted it and also found that it was in quad 4! bu the rest of the info makes sense as well. thank you!
+1993 everything was correct, but it was suppsoed to be 90 degress. I got it wrong. Could you explain ?
+128456 Mmmmm...I don't see how they got that ....but.....I'm not an expert on this !!!!
See the graph here : https://www.desmos.com/calculator/g6co3qmnlt
We can imagine these points as being in the complex plane
The line y = (-2/3)x goes through both points .....so...they are separated by 180°
Note that if we multiply (3 - 2i) by i^3 we get 3i^3 - 2i^4 = -3i - 2 = -2 - 3i which is a 90° rotation clockwise and puts the product in Q3
Maybe someone else on here knows why 90° is correct
