#1**+2 **

3 -2i lies in Quadrant IV

Multiplying this by i^2 gives us

(3 - 2i) * i^2 = 3i^2 - 2i^3 = - 3 - 2 (-i) = -3 + 2i

This is a 180° rotation counter-clockwise

The new product lies in Quadrant II

CPhill May 1, 2020

#2**+1 **

i jsut went and plotted it and also found that it was in quad 4! bu the rest of the info makes sense as well. thank you!

jjennylove
May 1, 2020

#4**0 **

everything was correct, but it was suppsoed to be 90 degress. I got it wrong. Could you explain ?

jjennylove
May 1, 2020

#5**+2 **

Mmmmm...I don't see how they got that ....but.....I'm not an expert on this !!!!

See the graph here : https://www.desmos.com/calculator/g6co3qmnlt

We can imagine these points as being in the complex plane

The line y = (-2/3)x goes through both points .....so...they are separated by 180°

Note that if we multiply (3 - 2i) by i^3 we get 3i^3 - 2i^4 = -3i - 2 = -2 - 3i which is a 90° rotation clockwise and puts the product in Q3

Maybe someone else on here knows why 90° is correct

CPhill
May 1, 2020