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(A) Find all values of \(y\) that satisfy the equation

\(\frac{y}{3} + 1 = \frac{y + 3}{y}\)

(B) Find all real numbers \(a\) that satisfy

\(\frac{1}{a^3 + 7} -7 = \frac{-a^3}{a^3 + 7}\)

(C) Find all \(y\) such that \(\dfrac{3y - 5}{6} = \dfrac{2y - 1}{3} + 2\)

 Jul 13, 2022
 #1
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(a) y = 3

(b) a = 2

 Jul 13, 2022
 #2
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(A) i also found that, but it says that there are more. maybe negative numbers too?

b) that seems incorrect. i wonder why..

 

Thank you for your response thoug!

Guest Jul 13, 2022

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