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# Help Please and Thank You

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Let $$\mathcal{R}$$ denote the circular region bounded by $$x^2+y^2=36$$$$.$$ The lines $$x=4$$ and $$y=3$$ partition $$\mathcal{R}$$ into four regions $$\mathcal{R}_1$$$$,$$$$\mathcal{R}_2,$$$$\mathcal{R}_3,$$ and $$\mathcal{R}_4.$$ Let $$[\mathcal{R}_i]$$ denote the area of region $$\mathcal{R}_i.$$ If $$[\mathcal{R}_1] > [\mathcal{R}_2] > [\mathcal{R}_3] > [\mathcal{R}_4]$$$$,$$ then compute $$[\mathcal{R}_1] - [\mathcal{R}_2] - [\mathcal{R}_3] + [\mathcal{R}_4].$$

Dec 19, 2019

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Heureka had an ingenious solution,  here  :

https://web2.0calc.com/questions/let-denote-the-circular-region-bounded-by-x-2-y-2

Dec 19, 2019
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Thanks! I understand the solution, too, now!