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# Help Please ASAP

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1.  In a certain country, the probability that a baby that is born is a boy is 0.52 and the probably that a baby that is born is a girl is 0.48. A family has two children. If X is the number of girls born to a family, find the probability that the family has 0, 1, or 2 girls.

(a)  Draw a tree diagram showing the possibilities for each outcome.

(b)  Create the binomial distribution table for p(x) .

Jan 8, 2019

#1
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B = boy, G = girl

a)
Probability of 2B is (0.52)(0.52) = 0.2704.
Probability of BG is (0.52)(0.48) = 0.2496
Probability of GB is the same as the probability of BG, so it is 0.2496.
Probability of 2G is (0.48)(0.48) = 0.2304.

b)
Number of girls born:

Table for p(x)
For zero girls and 2 boys, it is 0.2704.
For 1 girl and 1 boy, it is 0.4992.
For 2 girls, it is 0.2304.

- PM

#2
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Here is the tree for  part a).

0 child              1st child              2nd child

| -- Boy (27.04%)

_ Boy (52%) -------[

Start                   |                          | -- Girl (24.96%)

X -------------------|

|                          | -- Boy (24.96%)

|_ Girl (48%) --------[

|_ Girl (23.04%)

- PM

edited by PartialMathematician  Jan 8, 2019
edited by PartialMathematician  Jan 8, 2019
#3
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Excellent, PM....!!!!   Jan 9, 2019