Let f(x)=\frac{(x-2)^2-9}{3}. The equation y=f(x) is graphed, and the x- and y-intercepts of the graph are connected to form a polygon. What is the area of that polygon?
+1713 De latexed:
Let f(x)=\(\frac{(x-2)^2-9}{3}\). The equation y=f(x) is graphed, and the x- and y-intercepts of the graph are connected to form a polygon. What is the area of that polygon?
+118687 \(y=\frac{(x-2)^2-9}{3}\)
If y is 0 then solve for x.
Hint: there are 2 answers
If x is 0 solve for y
there will be one answer.
Now you have 3 points, join them to form a triangle.
If you sketch it you will see the base and the height very easily.
Now find the area of the triangle.
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This is a teaching answer, please do not answer over me with a fuller answer.
