Let f(x)=\frac{(x-2)^2-9}{3}. The equation y=f(x) is graphed, and the x- and y-intercepts of the graph are connected to form a polygon. What is the area of that polygon?

Guest Nov 14, 2019

#1**+1 **

De latexed:

Let f(x)=\(\frac{(x-2)^2-9}{3}\). The equation y=f(x) is graphed, and the x- and y-intercepts of the graph are connected to form a polygon. What is the area of that polygon?

tommarvoloriddle Nov 14, 2019

#2**+1 **

\(y=\frac{(x-2)^2-9}{3}\)

If y is 0 then solve for x.

Hint: there are 2 answers

If x is 0 solve for y

there will be one answer.

Now you have 3 points, join them to form a triangle.

If you sketch it you will see the base and the height very easily.

Now find the area of the triangle.

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**This is a teaching answer, please do not answer over me with a fuller answer.**

Melody Nov 14, 2019