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Let f(x)=\frac{(x-2)^2-9}{3}. The equation y=f(x) is graphed, and the x- and y-intercepts of the graph are connected to form a polygon. What is the area of that polygon?

 Nov 14, 2019
 #1
avatar+1681 
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De latexed:

 

Let f(x)=\(\frac{(x-2)^2-9}{3}\). The equation y=f(x) is graphed, and the x- and y-intercepts of the graph are connected to form a polygon. What is the area of that polygon?

 Nov 14, 2019
 #2
avatar+106027 
+1

\(y=\frac{(x-2)^2-9}{3}\)

 

 

If y is 0 then solve for x.

Hint: there are 2 answers

 

If x is 0 solve for y

there will be one answer.

 

Now you have 3 points, join them to form a triangle.

 

If you sketch it you will see the base and the height very easily.

Now find the area of the triangle.

 

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This is a teaching answer, please do not answer over me with a fuller answer.

 Nov 14, 2019

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