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Let f(x)=\frac{(x-2)^2-9}{3}. The equation y=f(x) is graphed, and the x- and y-intercepts of the graph are connected to form a polygon. What is the area of that polygon?

Nov 14, 2019

#1
+1681
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De latexed:

Let f(x)=$$\frac{(x-2)^2-9}{3}$$. The equation y=f(x) is graphed, and the x- and y-intercepts of the graph are connected to form a polygon. What is the area of that polygon?

Nov 14, 2019
#2
+106027
+1

$$y=\frac{(x-2)^2-9}{3}$$

If y is 0 then solve for x.

If x is 0 solve for y

Now you have 3 points, join them to form a triangle.

If you sketch it you will see the base and the height very easily.

Now find the area of the triangle.

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