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A regular hexagon has vertices at 1-2i, 0, a, b, c, and d clockwise in that order, as in the picture below: 

Then what is Im(a)? Btw, Im stands for imaginary axis

 Aug 20, 2021
 #1
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Im(a) = sqrt(3).

 Aug 20, 2021
 #2
avatar+19 
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That's wrong

 Aug 20, 2021
 #3
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Here are some useful equations:

I'll let you fill in the numbers.

 Aug 21, 2021
 #4
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How can I find sin(a)?

 Aug 21, 2021
 #5
avatar+32557 
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The first equation allows you to calculate \(\theta\)

Then you can calculate \(\beta\) from the second equation

Then you can calculate \(\alpha\) from the third equation

Then you can calculate \(\sin \alpha\)

 Aug 22, 2021
 #6
avatar+19 
0

Nevermind thanks for all the help!

 Aug 22, 2021
edited by YABOIIIIII  Aug 22, 2021

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