Find the value of y such that \(9^y = \dfrac{3^5\cdot 9^6}{27^3}.\) with explanation please
9^y =(3^5 * 3^(2*6) / (3)^(3*3)
9^y =(3^5 * 3^12) / 3^9
9^y =(3^(5+12)) / 3^9
9^y =3^17 / 3^9
9^y =3^(17 - 9)
9^y =3^8
3^(2y) =3^8
2y = 8
y = 4
+2864 So in other words, try using the exponent rules and simplifying the right side of the equation so the left side of the equation has the same base as the other side.
