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I need help understanding how to do this problem. Can anyone help me out?

 

 Oct 2, 2019
 #1
avatar+791 
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where the rest

 Oct 2, 2019
 #2
avatar+63 
+1

Sorry it must have got cut off. It wants me to find the mesure of arc EA.

Masterx4020  Oct 2, 2019
 #3
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I need help understanding how to do this problem. Can anyone help me out? 

 

I'm going to assume that what looks like a diameter is actually a diameter. 

 

AD is a straight line, which contains 180o  

The right angle is 90o plus the 52o totals 142o  

Subtract that from the 180o of AD and it leaves 38o for that small sliver of an angle (AB)

Since that angle is 38o then so is the other small sliver on the other side (DE)

Subtract the 38o (DE) from the straight line 180o (AD) and that leaves 142o for AE

 Oct 2, 2019
 #4
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I did that but when you add up the rest of the arcs it goes past 360 degreees. I don't think it is suppose to do so.

Masterx4020  Oct 2, 2019
 #5
avatar+791 
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agreeded with guest

travisio  Oct 2, 2019
 #9
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+2

 

when you add up the rest of the arcs it goes past 360 degreees  

 

I don't think so, MasterX4020.  Let's add them up.

 

AB   +   BC   +   CD   +   DE   +   EA 

38o  +   52o  +   90o  +   38o  +  142o  =  360o                                              

.

Guest Oct 2, 2019
 #6
avatar+791 
+2

52+90+38 = 180

142+38 = 180

 

line BE is 180

when you do the math the angle of 52+90+38=180

 

so..

 

The same goes for AD 52+90+38=180

 

There for 142+38=180

 

So...

 

180+180=360

 Oct 2, 2019
 #7
avatar+10646 
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180° - 90°-52° = 38°

laugh

 Oct 2, 2019
 #8
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I'm not sure about this, because i'm not sure if DA and EB are diameters of the circle or not. If they are, then I can answer.

 

However, if we assume that EB is the diameter...

Arc EB is 180 degrees (the arc that goes through points D and C).

All together, then angle DOC (where O is the center) + angle BOC + angle EOD = 180

We already have 90+52 which is 142

180-142 = 38

So EOD is 38 degrees.

 

Now, arc AD is 180 degrees (again assuming that AD is the diameter)

So simply do 180-38 which is 142

So arc EA is 142.

 

You are very welcome!

:P

 Oct 2, 2019
 #10
avatar+63 
+1

Thank you everyone who helped me. I understand it now. I have another question I am struggleing with and it is this one.

IT wants me to find angle LPN. How do I Get the angles on inside the quadraltiral? Thanks again.

 

 Oct 2, 2019
 #14
avatar+791 
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i do not know this one sorry

travisio  Oct 2, 2019
 #15
avatar+976 
+2

Here's something that you need to know to solve this problem: It's a Cyclic Quadrilateral.

Cyclic Quadrilaterals are basically quadrilaterals that can be inscribed in a circle.

In Cyclic Quadrilateral LMNP, angle L + angle N = 180, and angle M + angle P = 180. That's just the property of one.

 

Angle M = arc LP + arc NP / 2, or 123 degrees.

So angle P = 180-123 = 57 degrees.

 

You are very welcome!

:P

CoolStuffYT  Oct 2, 2019
 #11
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Masterx4020: On the first question: Did you want the angle EA or the "Length of arc EA"? They are 2 different things.

 Oct 2, 2019
 #12
avatar+63 
+1

it was the mesure of the arc, Not the length.

Masterx4020  Oct 2, 2019
 #13
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0

 

Did you want the angle EA or the "Length of arc EA"? They are 2 different things.

 

The length of EA, as a segment of the circumference, was not the question. 

 

.

Guest Oct 2, 2019

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