Help please Geometry!

where the rest

I need help understanding how to do this problem. Can anyone help me out? 

I'm going to assume that what looks like a diameter is actually a diameter. 

AD is a straight line, which contains 180^o  

The right angle is 90^o plus the 52^o totals 142^o  

Subtract that from the 180^o of AD and it leaves 38^o for that small sliver of an angle (AB)

Since that angle is 38^o then so is the other small sliver on the other side (DE)

Subtract the 38^o (DE) from the straight line 180^o (AD) and that leaves 142^o for AE

52+90+38 = 180

142+38 = 180

line BE is 180

when you do the math the angle of 52+90+38=180

so..

The same goes for AD 52+90+38=180

There for 142+38=180

So...

180+180=360

180° - 90°-52° = 38°

I'm not sure about this, because i'm not sure if DA and EB are diameters of the circle or not. If they are, then I can answer.

However, if we assume that EB is the diameter...

Arc EB is 180 degrees (the arc that goes through points D and C).

All together, then angle DOC (where O is the center) + angle BOC + angle EOD = 180

We already have 90+52 which is 142

180-142 = 38

So EOD is 38 degrees.

Now, arc AD is 180 degrees (again assuming that AD is the diameter)

So simply do 180-38 which is 142

So arc EA is 142.

You are very welcome!

:P

Thank you everyone who helped me. I understand it now. I have another question I am struggleing with and it is this one.

IT wants me to find angle LPN. How do I Get the angles on inside the quadraltiral? Thanks again.

Masterx4020: On the first question: Did you want the angle EA or the "Length of arc EA"? They are 2 different things.