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# Help please, im not sure how to solve this

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Every time I use a piece of scrap paper, I crumple it up and try to shoot it inside the recycling bin across the room. I'm pretty good at it: If I shoot $5$ pieces of paper at the recycling bin, at least one of them will make it inside the recycling bin with probability $\frac{211}{243}$. If I shoot $6$ pieces of paper at the recycling bin, what's the probability at least two of them make it inside the recycling bin?

Jul 16, 2022

#1
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Note that because $$243 = 3^5$$, we know that the probability that you make a shot is $${ x \over 3}$$ (because he makes 5 shots)

The probability of making at least 1 shot is the same as $$1 - \text{probability of failing every time}$$

From the given info, we know that the probability of failing every time is $$1 - {211 \over 2443} = {32 \over 243}$$

This means that $$x = \sqrt[5]{32} = 2$$, so the probability of making any free throw is $$2 \over 3$$.

Can you take it from here?

Jul 16, 2022
#2
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BuilderBoi, do you like to $$\text{su}$$$$\text{ck}$$ $$\text{co}$$$$\text{ck}$$?

Guest Jul 16, 2022
#3
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could you please explain further, and what is x in x/3

Jul 20, 2022