Help please log_2(x^2+2x)=3

I assume this might be......

log₂(x^2 + 2x) = 3     if so, we can write

2^3  = x^2 + 2x    →  8 = x^2 + 2x        rearrange

x^2 + 2x - 8 = 0      factor

(x + 4) (x - 2)  = 0      and setting each factor to 0, we have that x = -4   and x = 2

We must reject x = 2, because it leads to taking a log of 0  in the original problem, and this is undefined

x = -4  is the only solution