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Show Your Work!

Solution A is an 80% acid solution. Solution B is a 30% acid solution.

(a) How many mL of Solution A must be added to 500mL of Solution B in order to produce a 70% acid solution?

(b) How many mL of Solution A and how many mL of Solution B must be combined to form a 100mL solution that is 50% acid?

(c) Is there a combination of Solution A and Solution B that is 90% acid?

 Mar 24, 2020
edited by CPhilFanboy  Mar 24, 2020
 #1
avatar+111330 
+2

(a) , (b)   can't answer  these  unless we know  the ml  of Solution B

 

 

(c) This is impossible.....the strongest possible  solution would  be  a pure solution of  A =  80%

 

There's no way we  can get  a solution that is 90% acid

 

 

 

 

 

cool cool cool 

 Mar 24, 2020
 #2
avatar+133 
+2

I fixed it.

CPhilFanboy  Mar 24, 2020
 #3
avatar+111330 
+2

OK....here we go  .....

 

(a)  Let x  be  the   mL of Solution A that we need

 

So....we  have  this equation 

 

.80x  +  .30 (500) = .70 ( 500 + x)    simplify

 

.80x + 150 = 350  + .70x

 

.80x - 70x =  350 - 150

 

.10x=  200    divide both  sides  by  ,10

 

x =  2000  (mL  of  Solution A  )

 

 

 

cool cool cool 

CPhill  Mar 24, 2020
 #5
avatar+1970 
+1

Great job, Chris!

CalTheGreat  Mar 24, 2020
 #4
avatar+111330 
+1

(b)      Let x  be the mL of A

Then  100 - x  is the  mL of B

 

And we have that

 

.80x  + .30 (100-x)  =  .50(100)   simplify

 

.80x   + 30  - .30x  =  50

 

.80x - .30x  =  50  - 30

 

.50x  =  20       divide both sides by .50

 

x = 40  = mL of A

 

100 - 40  =  60  mL  of B

 

 

 

cool cool cool

 Mar 24, 2020

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