There were 180 more bags in shop A than shop B at first. After 1/5 of the bags were transferred from shop A to shop B, there were 24 more bags in shop B than shop A. How many bags were there in shop B at first?

Guest May 8, 2022

#1**+1 **

Originally there are B bags in shop B and B+180 bage in shop A

then after transfer

there will be

\(B+\frac{B+180}{5}\;\;bags\;\ in\; shop\;\;B\)

and

\(\frac{4}{5}(B+180)\) bags in shop A

You can take it from there.

Melody May 8, 2022

#2**+1 **

=> Let assume the number of bags in shop (A) be x and in shop (B) be y

Now, According to question :-

x = 180 + y ------ (1)

Also (180 + y) * 1/5 were transferred to shop (B)

So, y + (180 + y) * 1/5 = 24 + 4/5 (180 + y)

=> y + 36 + y/5 = 24 + 144 + 4/5y

=> y = y/5 - 4/5y = 144 + 24 - 36

v> 2/5y = 132 => y = 330

[Total No. of Bags in Shop (B) = 330]

Slimesewer May 10, 2022