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There were 180 more bags in shop A than shop B at first. After 1/5 of the bags were transferred from shop A to shop B, there were 24 more bags in shop B than shop A. How many bags were there in shop B at first?

 May 8, 2022
 #1
avatar+118128 
+1

Originally there are  B bags in shop B   and  B+180 bage in shop A

 

then after transfer

 there will be 

  \(B+\frac{B+180}{5}\;\;bags\;\ in\; shop\;\;B\)

 

and

\(\frac{4}{5}(B+180)\)    bags in shop A

 

You can take it from there.

 May 8, 2022
 #2
avatar+231 
+1

=> Let assume the number of bags in shop (A) be x and in shop (B) be y

Now, According to question :-

        x = 180 + y ------ (1)

Also (180 + y) * 1/5 were transferred to shop (B)

So, y + (180 + y) * 1/5 = 24 + 4/5 (180 + y)

=> y + 36 + y/5 = 24 + 144 + 4/5y

=> y = y/5 - 4/5y = 144 + 24 - 36

v> 2/5y = 132 => y = 330

[Total No. of Bags in Shop (B) = 330]

 May 10, 2022
edited by Slimesewer  May 10, 2022

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