Suppose $d\not=0$. We can write $\left(12d+13+14d^2\right)+\left(2d+1\right)$, in the form $ad+b+cd^2$, where $a$, $b$, and $c$ are integers. Find $a+b+c$.
+895 d≠0
(12d+13+14d2)+(2d+1)
This is more simple than it seems.
Combine like terms.
14d+14+14d2
Since the form is ad+b+cd2, apply what it looks like to your formula.
a=14,b=14,c=14
