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Suppose $d\not=0$. We can write $\left(12d+13+14d^2\right)+\left(2d+1\right)$, in the form $ad+b+cd^2$, where $a$, $b$, and $c$ are integers. Find $a+b+c$.

Guest Oct 12, 2017
 #1
avatar+771 
+2

\(d\not=0\)

\(\left(12d+13+14d^2\right)+\left(2d+1\right)\)

This is more simple than it seems.

Combine like terms.

\(14d+14+14d^2\)

Since the form is ad+b+cd2, apply what it looks like to your formula.

\(a=14, b=14, c=14\)

AdamTaurus  Oct 12, 2017
 #2
avatar+89909 
0

Nice, AT...!!!!

 

cool cool cool‚Äč

CPhill  Oct 12, 2017
 #3
avatar+771 
+1

Thanks!smiley

AdamTaurus  Oct 12, 2017

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