Suppose $d\not=0$. We can write $\left(12d+13+14d^2\right)+\left(2d+1\right)$, in the form $ad+b+cd^2$, where $a$, $b$, and $c$ are integers. Find $a+b+c$.
+895 \(d\not=0\)
\(\left(12d+13+14d^2\right)+\left(2d+1\right)\)
This is more simple than it seems.
Combine like terms.
\(14d+14+14d^2\)
Since the form is ad+b+cd2, apply what it looks like to your formula.
\(a=14, b=14, c=14\)
