Suppose $d\not=0$. We can write $\left(12d+13+14d^2\right)+\left(2d+1\right)$, in the form $ad+b+cd^2$, where $a$, $b$, and $c$ are integers. Find $a+b+c$.

Guest Oct 12, 2017

#1**+2 **

\(d\not=0\)

\(\left(12d+13+14d^2\right)+\left(2d+1\right)\)

This is more simple than it seems.

Combine like terms.

\(14d+14+14d^2\)

Since the form is ad+b+cd^{2}, apply what it looks like to your formula.

\(a=14, b=14, c=14\)

AdamTaurus
Oct 12, 2017