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Suppose $d\not=0$. We can write $\left(12d+13+14d^2\right)+\left(2d+1\right)$, in the form $ad+b+cd^2$, where $a$, $b$, and $c$ are integers. Find $a+b+c$.

Guest Oct 12, 2017
#1
+771
+2

$$d\not=0$$

$$\left(12d+13+14d^2\right)+\left(2d+1\right)$$

This is more simple than it seems.

Combine like terms.

$$14d+14+14d^2$$

Since the form is ad+b+cd2, apply what it looks like to your formula.

$$a=14, b=14, c=14$$

#2
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Nice, AT...!!!!

CPhill  Oct 12, 2017
#3
+771
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Thanks!